In statistics, a confidence interval (CI) is a particular kind of interval estimate of a population parameter. Instead of estimating the parameter by a single value, an interval likely to include the parameter is given. Thus, confidence intervals are used to indicate the reliability of an estimate. How likely the interval is to contain the parameter is determined by the confidence level or confidence coefficient. Increasing the desired confidence level will widen the confidence interval.

A confidence interval is always qualified by a particular confidence level, usually expressed as a percentage; thus one speaks of a "95% confidence interval". The end points of the confidence interval are referred to as confidence limits. For a given estimation procedure in a given situation, the higher the confidence level, the wider the confidence interval will be.

The calculation of a confidence interval generally requires assumptions about the nature of the estimation process – it is primarily a parametric method – for example, it may depend on an assumption that the distribution of the population from which the sample came is normal. As such, confidence intervals as discussed below are not robust statistics, though modifications can be made to add robustness – see robust confidence intervals.

Confidence intervals are used within Neyman–Pearson (frequentist) statistics; in Bayesian statistics a similar role is played by the credible interval, but the credible interval and confidence interval have different conceptual foundations and in general they take different values. As part of the general debate between frequentism and Bayesian statistics, there is disagreement about which of these statistics is more useful and appropriate, as discussed in alternatives and critiques.

From Wikipedia under the GNU Free Documentation License
Thu Feb 18 09:28:16 2010

I need help with this statistics question on Confidence Intervals?
Q. In the study of the efficiency of a new computer search routine a random sample of 300 records was selected from a data base. The sample mean search time was 2.26 seconds and its standard deviation was 1.211 seconds. (a)Give an estimate of the mean search time for the population of all records in the data base and calculate its standard error. (b)Construct a 99% confidence interval for the population mean search time. (c)Estimate the sample size required to reduce the width of the 99% confidence interval to 0.2 seconds.
Asked by Thirdman - Thu Mar 5 14:16:07 2009 - - 1 Answers - 0 Comments

A. a) population mean search time is approx equal to sample search time (for samples > 30) = 2.26 secs standard error = standard deviation of mean/sqrt sample size = 1.211/17.32 = 0.07 b) 2.2 -> 2.4 c) = 1320 (this is not my best subject, so I can't guarantee my answers are correct)
Answered by Martin F - Thu Mar 5 14:40:23 2009

What effect does standard deviation have on confidence intervals?
Q. What effect does standard deviation have on confidence intervals?
Asked by St. Nick - Sun Aug 3 00:14:52 2008 - - 1 Answers - 0 Comments

A. A confidence interval for a mean is given by u z where u denotes the estimated mean (should be mu-bar but I can't find that symbol), z is the z-score corresponding to the confidence level, and is the standard deviation. If increases, then the length of the confidence interval increases and if decreases, then the length of the confidence interval decreases. Maybe this is easier to understand - in effect, if the data has a small variance (standard deviation squared) you would expect to be more confident given the same range for data with a larger variance. Hope this helps you!
Answered by Amy J - Sun Aug 3 00:57:02 2008

How to find confidence intervals for data sets?
Q. Given the data set from a normal distribution: 63,57,58,60. Construct a 90% CI for . Given: = 10.1 as well as Given the data set from a uniform distribution: 63, 57,58, 60, 59, 59, 61, 56, 60. Construct a 90% CI for . (Assume 9 is large enough for the CLT to hold).
Asked by funkijim9 - Thu Jun 12 01:03:30 2008 - - 1 Answers - 0 Comments

A. ONE-SAMPLE "t" confidence intervals data set {63,57,58,60} 1. t-critical value [2.132] "look-up" table for 90% "two-sided" Confidence Interval (n = 4 "degrees of freedom") 2. Confidence Interval [37.97, 81.03] x-bar +/- (t-critical value) * x-bar = sample average [59.5] = standard deviation [10.1] data set {63, 57,58, 60, 59, 59, 61, 56, 60} 1. t-critical value [1.833] "look-up" table for 90% "two-sided" Confidence Interval (n = 9 "degrees of freedom") 2. Confidence Interval [57.93, 60.51] x-bar +/- (t-critical value) * s/SQRT(n) x-bar = sample average [59.22] s = sample standard deviation [2.11]
Answered by M - Thu Jun 12 11:07:50 2008

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